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Arlecino [84]
3 years ago
9

What is the area of this cross section of this rectangular prism? Enter your answer in the box.

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

16.

Step-by-step explanation:

Is there a picture?

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Find all real numbers z for which the equation (z-5)x^2-zx+5=0 only has one real solution. If you find more than one, then list
Nataliya [291]

Step-by-step explanation:

For the quadratic equation to have 1 repeated real solution, the discriminant b² - 4ac must be zero.

=> (-z)² - 4(z - 5)(5) = 0

=> z² - 20(z - 5) = 0

=> z² - 20z + 100 = 0

=> (z - 10)² = 0

Therefore z = 10.

7 0
3 years ago
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?
anyanavicka [17]

Answer: D.a^2 + b^2 < c^2

Step-by-step explanation:

In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.

∵ In a triangle, the side opposite to the largest angle is largest.

Thus, the largest side in then given obtuse triangle= c

The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.

Therefore, we have

a^2 + b^2 < c^2

5 0
3 years ago
Is the dilation of -3/4 a contraction or an expansion?
lyudmila [28]
I don't under stand
5 0
3 years ago
what’s the difference between the area of the larger circle and the area of the smaller circle? in pi
Arisa [49]

Answer:

105 pi m^2

Step-by-step explanation:

radius squared - radius squared =

(16+3)^2 - 16^2 =

19^2 - 16^2 =

361-256= 105

7 0
3 years ago
FIND THE THIRD,FIFTH AND TENTH TERM SEQUENCE DESCRIBED BY EACH RULE
Karolina [17]
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

</span><span>THIRD
</span><span>A3=4+(3-1)(-5)
A3 = -6

A(3)=-2(3-1)(-5)
A3 = 20
 </span><span>
FIFTH
</span>A5=4+(5-1)(-5)
A5 = -16

A(5)=-2(5-1)(-5)
A5 = 40<span>

TENTH
</span>A10=4+(10-1)(-5)
A10 = -41

A(10)=-2(10-1)(-5)
A10 = 90
8 0
3 years ago
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