Answer:
x = -3 +/- square root(22)
Step-by-step explanation:
x = -b +/- square root(b^2 - 4ac) / 2a
ax^2 + bx + c = 0
these are both the quadratic formula but one is solved for the x and another for 0
a= 1
b= 6
c = -13
x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)
x = -6 +/- sqrt( 36 + 52) / 2
x= -6 +/- sqrt (88) / 2
sqrt of 88 = 2 x sqrt (22)
divide 2 on each
x= -3 +/- sqrt (22)
Answer:

Step-by-step explanation:
The standard form of an equation of a circle:

(h, k) - center
r - radius
We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).
The midpoint of a diameter is a center of a circle.
The formula of a midpoint:

Substitute:

We have h = -6 and k = -10.
The radius is the distance between a center and the point on a circumference of a circle.
The formula of a distance between two points:

Substitute (-6, -10) and (-8, -6):

Finally we have

Answer:
![r = \sqrt[3]{\dfrac{3V}{4 \pi}}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20)
Step-by-step explanation:




![r = \sqrt[3]{\dfrac{3V}{4 \pi}}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20)
Answer:
The other angle would be equal to 133 degrees.
Step-by-step explanation:
All linear pairs are supplementary angles, which means that they are equal to 180. So we can find the second angle by using the following angle.
47 + x = 180
x = 133
Question:
Approximate log base b of x, log_b(x).
Of course x can't be negative, and b > 1.
Answer:
f(x) = (-1/x + 1) / (-1/b + 1)
Step-by-step explanation:
log(1) is zero for any base.
log is strictly increasing.
log_b(b) = 1
As x descends to zero, log(x) diverges to -infinity
Graph of f(x) = (-1/x + 1)/a is reminiscent of log(x), with f(1) = 0.
Find a such that f(b) = 1
1 = f(b) = (-1/b + 1)/a
a = (-1/b + 1)
Substitute for a:
f(x) = (-1/x + 1) / (-1/b + 1)
f(1) = 0
f(b) = (-1/b + 1) / (-1/b + 1) = 1