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3 years ago

Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!! HELP !!!!!!!

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

3 0

Y= 2x + 3

You can tell because the slope is the same :)

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Out of a group of 30 volunteers, 17 people are chosen to participate in a survey about the number of phone calls they make each

mel-nik [20]

Answer:

i dont know

Step-by-step explanation:

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2 years ago

Read 2 more answers

8) Monica spent $34 on brownies and cookies. We know brownies cost $2

Anna [14]

The answer is

2b + .75c = 34

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2 years ago

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Help needed ASAP will give BRAINLIEST

grin007 [14]

Answer:

Step-by-step explanation:

Recall that the sum of the (3) interior angles of a triangle <em>must</em> equate to 180.

In other words:

$(55)+(20)+(x)=180$

Where x is our unknown angle. So, we need to solve for x.

On the left, add 55 and 20:

$75+x=180$

Subtract 75 from both sides. The left side cancels:

$x=105$

Therefore, the third angle is 105 degrees.

Our answer is C.

7 0

3 years ago

Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

4 0

3 years ago

Find the midpoint of the line segment with end coordinates of:(−1,7) and (3,−2)

SOVA2 [1]

Answer:

Step-by-step explanation:

mid point formula = (x1+x2/2 , y1+y2/2)

hence putt the values we get,

mid point = ( -1+3/2 , 7-2/2)

= (1 , 2.5)

5 0

2 years ago