d - 3 = (-8)
+3 +3
d = -5
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Answer:
8
Step-by-step explanation:
X - 5 = x^2
i) 0 - 5 = -5^2 = 25
ii) 4 - 5 = -1^2 = 1
iii) -4 - 5 = -9^2 = 81
If this were to be graphed, the independent variable would be the price of the ticket for the rides. The dependent variable would be the total cost.
The fair admission is not a variable because it is a constant price for every single person who goes into the fair.
The problem asks to use y to represent the total cost and x to represent the number of ride tickets. In order to fully write out the equation, we have to figure out what the fair admission costs.
43.75 = 1.25(25) + b
*b represents the fair admission
Multiply 1.25 by 25
43.75 = 31.25 + b
Subtract 31.25 to find what b costs.
12.50 = b
The fair admission costs $12.50.
Solution: y = 1.25x + 12.50
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
