Answer:
a) 2.188
b) John's rent is not an outlier
c) His rent has to be higher than $1,235 to be an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard University is $780 with a standard deviation of $208.
(a) John’s rent is $1,235. What is his standardized z-score?
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $1235
μ is the population mean = $780
σ is the population standard deviation = $208
Hence,
z = 1235 - 780/208
z = 2.1875
Approximately to 3 decimal place = 2.188
(b) Is John’s rent an outlier?
No it isn't
(c) How high would the rent have to be to qualify as an outlier?
John’s rent would have to be higher than $1235
18 : (18+6+32) = 18 : 56 or 18/56
Divide each by 2 = 9 : 28 or 9/28 whichever way you are writing the ratio.
Answer:
https://forms.gle/VqfekaGgk8cfJhPW9
Step-by-step explanation:
Answer:
See proof below
Step-by-step explanation
cot^2(x) - csc^2(x) = -1
In trigonometry identity
cot^2x = cos²x/sin²x
Csc²x = 1/sin²x
Substitute into the original expression
cos²x/sin²x - 1/sin²x
Find the LCM
(Cos²x-1)/sin²x .... *
Recall that sin²x+cos²x = 1
Sin²x = 1-cos²x
-sin²x = -1+cos²x
-sin²x = cos²x-1 .... **
Substitute ** into *
(Cos²x-1)/sin²x
-sin²x/sin²x
= -1 (RHS)
Therefore cot^2(x) - csc^2(x) = -1 (Proved!)
The product of algebraic expression is 
.
We have to determine
What is the product of d - 9 and 2d^2+11d-4?
<h3>How to find the product of two algebraic expressions?</h3>
The product of the algebraic expressions is also an algebraic expression. Lastly, simplify the algebraic expression by the fundamental operations of terms for combining the like terms.
Therefore,
The product of algebraic expression is;
Hence, the product of algebraic expression is .
To know more about the Product click the link given below.
brainly.com/question/1337024
