Answer: The answer is: f(x) = 2x^2 + 40x + 200
Explanation:
Given: x is the width of the Artwork
Let W be the Width of the Frame
Let L be the Length of the Frame
Width = x + 10
Length = Width * 2, so by substitution, Length = 2(x + 10)
Area = Width * Length
By substitution:
Area = (x + 10) * 2(x + 10)
f(x) = (x + 10) * (2x + 20)
f(x) = 2x^2 + 20x + 20x + 200
f(x) = 2x^2 + 40x + 200
To test this, if a picture 8" wide is put in this frame, the width would be 8+10 or 18 inches. The length would be twice the width, or 36 inches. The Area is 18 x 36 = 648.
Using the formula:
f(8) = (2 * 8^2) + (40 * 8) + 200
f(8) = (2 * 64) + 320 + 200
f(8) = 128 + 320 + 200
f(8) = 648
Answer:
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Explanation:
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F'(x)=(2/3(x^2-2x-1)^-1/3 )*(2x-2) chain rule here
f'(0) is equals to substitute x with 0. Which gives
f'(0)= (2/3(-1)^-1/3)*(-2)
Plug in the calculator, and your answer is ready
