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3 years ago

Someone help please!!

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

7 0

Answer:

4) (1, 3)

Step-by-step explanation:

this ordered pair is the only one with an x-value not already defined in the function (x-values cannot be duplicated in functions)

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3 years ago

Which best describes the relationship between the line that passes through the points (-9, -7) and (-12, -2) and the line

o-na [289]

Answer:

Step-by-step explanation:

The equation of the line that passes through the points (-9,-7) and (-12,-2) is

y = -5/3x-22

and

equation of the line that passes through the points (1, 9) and (6, 6) is

y = -3/5x+48/5

clearly it is not the same line,

$\frac{-5}{3}.\frac{-3}{5} \neq -1$ (lines are not perpendicular)

$\frac{-5}{3}\neq \frac{-3}{5}$ (not parallel)

8 0

2 years ago

PLEASE HELP WITH ALGEBRA QUESTIONS!!

kenny6666 [7]

1. (f+g)(x) = f(x) +g(x)
.. = (x^2-36) +(x^3+2x^2-10)
.. = x^3 +3x^2 -46

2. (f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81

3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10

5 0

4 years ago

Kiara opened an RRSP deposit account on December 1, 2008 with a deposit of $1,700. She added $1,700 on January 1, 2010, and $1,7

Angelina_Jolie [31]

Answer:

The total balance on December 1, 2016 is B = $7356.28

Step-by-step explanation:

I am going to call B1 the balance for the first deposit, B2 the balance for the second deposit and B3 for the third deposit.

This is a compound interest problem.

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

n: number of times that interest is compounded per unit t

t: time the money is invested or borrowed for.

First step: Balance B1 on December 1, 2016

A = amount of money = B1

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t = 8 years

$B1 = 1700(1 + \frac{0.056}{12})^{96}$

$B1 = $2658.17$

Second step: Balance B2 on December 1, 2016

A = B3

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t: From January 1, 2010 to December 1, 2016 there are 6 years and 11 months. 11 months is 0.92 of a year. So

t = 6.92

$B2 = 1700(1 + \frac{0.056}{12})^{83.04}$

$B2 = $2502.39$

Third step: Balance B3 on December 1, 2016

A = B3

P = 1700

r = 0.056

n = 12

t: 4 years and 7 months. 7 months is 7/12 = 0.58. So t = 4.58 years.

$B3 = 1700(1 + \frac{0.056}{12})^{54.96}$

$B3 = $2195.72$

Final step: Total balance on December 1, 2016

B = 2195.72 + 2502.39 + 2658.17

B = $7356.28

So the total balance on December 1, 2016 is B = $7356.28

6 0

4 years ago

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

x - x0 53 - 47 6

The z-score formula is z = --------------- = --------------- = -------- ≈ 0.55

sigma 11 11

6 0

2 years ago