This problem can be completed in 2 ways. Both are acceptable.
Option 1:This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.

The area of one of the triangles is half the base times the height.

The other triangle must have that area too.

The area is 56 square centimeters.
Option 2:We can use the area formula for the trapezoid.

Where

is the length of the shorter base
and

is the length of the longer base
and

is the height.
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.


Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.
~For this problem, you need to divide.
~The easy way that I think might help you is if you change the fraction into a decimal.
Now divide $8.47 by 0.875
The price per pound of the coffee was $9.68
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is

, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 =
8.88 mg.</span>
Answer:
x = 7 and 3/2
Step-by-step explanation:
We can say:
x - 7 = 0 and 2x - 3 = 0
<em>Lets solve for x - 7 = 0 first:</em>
Add 7 to each side of "="
=> <u>x = 7</u>
<em>Now lets solve for 2x - 3 = 0</em>
First add 3 to each side of "="
=> 2x = 3
Now divide each side by 2
<u>=> x = 3/2</u>
Hope this helps!
I am presuming that the question is who won or by how much did the winner win.
distance equals rate times time, or d = r*t
For the Hare d = 1600 and r = 10
1600 = 10 t
Divide both sides by 10
t = 160
The hare finished in 160 seconds
For the tortoise d = 1600 - 780 = 820 (due to the head start) and r = 5.3
820= 5.3 t
Divide both sides by 5.3
t = 154.72 (rounded to the hundredths place)
The tortoise won by 5. 28 seconds (160-154.72)