Answer: according to mathbitshomework.com: “When graphing a linear inequality on a number line, use an open circle for "less than" or "greater than", and a closed circle for "less than or equal to" or "greater than or equal to". ... The solution set for this problem will be the full graph of both inequalities, since the two inequalities do not overlap.”
Step-by-step explanation:
punan Ang nga patlang sa bawat bilang sa pamamagitan ng pagtukoy ng multiples nito.5,45,___,___,135
28,35,42,____,____
60,_____,80,___,100
125,175,__,___,325
105,126,147,___,___
120,___,150,165,___
100,125,150,___,___
240,___,____,252,__256
360,___450,540,____,____
160,___,____,280,320
Answer:
i believe its 6 units
Step-by-step explanation:
this is because you can slip the triangle into two different triangles and then find both their areas and combine them
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
brainly.com/question/9199238
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When comparing correlation, focus on the MAGNITUDE of r:
Compare |0.828| with |-0.879|. Which magnitue is greater? The r value with greater magnitude represents the stronger correlation.