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RUDIKE [14]
3 years ago
13

17. Mrs. King took 12 crates packed with lunch boxes on a field trip. Each crate had 6 lunch boxes inside. How many lunch boxes

were there altogether? Write a multiplication sentence to solve. IRROR​
Mathematics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

12 x 6 = 72

Step-by-step explanation:

if she took 12 crates each with 6 boxes inside of them thats 12 x 6 lol

simple math moment

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umka21 [38]

Answer:

x+(4x-85)=90

answer is d

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4 years ago
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Line K has the equation 9x-4y=-5x4.
Yuki888 [10]

Answer:

y = (9/4)x + 2, given that I've assume the correct meaning of "-5x4."

Step-by-step explanation:

A parallel line has the same slope as the reference line,

The reference line is 9x-4y = -5x4, as written.  I'm not sure the 4 belongs, but I'll assume it is written correctly.  I'm not sure if the term -5x4 is meant to mean -5x^4, -20x or -20.  I'll assume -20:

9x-4y = -20

Put the equation into standard slope-intercept form:  Y = mx + b, where m is the slope and b is the y-intercept (the value of y when  x = 0).

-4y = -9x - 20

y = (9/4)x + 5

This line has a slope of (9/4).  The parallel line will have the same slope.

y = (9/4)x + b

We can find a value of b that would shift this line to include (4,7) by using this point in the equation:

y = (9/4)x + b

7 = (9/4)(4) + b

7  = 9 + b

b = 2

The equation of a line parallel to the reference line is y = (9/4)x + 2

5 0
3 years ago
Which best describes a triangle with side links of 3 inches 4 inches and 8 inches ?
lisov135 [29]
It would be a scalene triangle.
7 0
3 years ago
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ALGEBRA II // MODULE 1
natita [175]

Answer:

1. x = 3

2.x = 6

3. x = 5

I hope this helps you :D

3 0
3 years ago
Please help if u cannot skip
posledela

The statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

<h3>How to determine which statement is true?</h3>

To determine which statement is true, we need to know the conditions for continuity and differentiablity of a function.

<h3>Conditions for continuity and differentiablity of a function.</h3>
  • For a function f(x) to be continuous at a point x = a, then both the left hand limit of f(x) and the right hand limit of f(x) as x → a must be equal. That is \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x). So,  \lim_{x \to a^{} } f(x) must exist since  \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x) =  \lim_{x \to a^{} } f(x)
  • Also, for a function to be differentiable at a point x = a, it must also exist at x = a

So, since f(x) = {x² - 1 if -1 ≤ x ≤ 3 and x²/3 if 3 < x ≤ 8}

From the equality on the first condition,we see that f(x) is exists at x = 3 but is not continuous since f(x) changes to another function when x > 3. So,left hand limit of f(x) and the right hand limit of f(x) as x → 3 are not equal.

That is \lim_{x \to 3^{-} } f(x) \neq   \lim_{x \to 3^{+} } f(x) . Thus, the function is discontinuous at x = 3.

For differentiability, both conditions must be met. Since only one condition is met, it is non-differentiable.

So, the function is discontinuous and non-differentiable at x = 3.

So, the statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

Learn more about continuity of a function here:

brainly.com/question/24177259

#SPJ1

4 0
2 years ago
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