Answer:
A. All of the elements of secondArray will get copied to firstArray.
Explanation:
The correct iteration code is:
for(i =0; i<4;++i) {
largerArray[i] = smallerArray[i];
}
From the question, we understand that the largerArray has a size of 4 elements while the smallerArray has a size of 3 elements
Take for instance largerArray is {1,2,3,4} and smallerArray is {5,6,7}
Next, we analyze the loop
1. for(i =0; i<4;++i) { --->This iterates from index 0 to index 3
2. largerArray[i] = smallerArray[i]; ---- > This assigns the elements of the smallerArray to largerArray.
However, it should be noted that the smallerArray has a maximum index of 2 while the largerArray has a maximum index of 3
The content of largerArray after the iteration will be:
largerArray = {5,6,7,5}
This is so because,
When i = 0
largerArray[0] = smallerArray[0] = 5
When i = 1
largerArray[1] = smallerArray[1] = 6
When i = 2
largerArray[2] = smallerArray[2] = 7
When i = 3
largerArray[3] = smallerArray[0] = 5
Notice that the last iteration refers to smallerArray[0]; this is so because index 3 do not exist in smallerArray. Hence, the index will be returned to the first index of the smallerArray
Taking largerArray as the firstArray and smallerArray as the secondArray.
We can conclude that option A answers the question because all elements in smallerArray is copied to firstArray
