Answer:
Machine Language.
Explanation:
The most basic language that is used by computers so that they can control the operation of the on/off switches in the circuitry is Machine language.
Machine Language is a low level language is a collection of binary digits or bits that is understood by the computers.Computers are capable of understanding only machine language.
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D that is the answer but I need 20 words to send this text
The four standard layers of a layered architecture are:
- presentation,
- business,
- persistence,
- database.
<h3>What is a Layered Architecture?</h3>
This refers to the architectural style that is used to show components with similar functions in horizontal layers that have specific roles.
Hence, we can see that no generic info system architecture was attached to the answer, so it would be impossible to create a layered architecture, so a general overview was given about layered architecture.
Read more about layered architecture here:
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Answer:
# include <iostream>
#include<stdio.h>
using namespace std;
bool IsLeapYear(int y)
int main()
{
int y;
cout<<"Enter the Year to check Leap or Not"<<endl;
cin>>y;
IsLeapYear(int y);
getch();
}
bool IsLeapYear(int y)
{
if (y%4==0)
{
if (y%100==0)
{
if (y%400==0 )
{
cout<"The year is leap Year";
}
else
{
cout<<" The year is not Leap Year";
}
}
else
{
cout<<"The year is Leap Year" ;
}
}
else
{
cout<<"The year is not Leap Year";
}
}
Explanation:
In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.
To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.
