Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
Answer:
Each student club must contribute $ 33.33 in order to meet the fundraising goal.
Step-by-step explanation:
Given that a school fundraiser has a minimum target of $ 500. Faculty have donated $ 100 and there are 12 student clubs that are participating with different activities, to determine how much money should each club raise to meet the fundraising goal, the following calculation must be performed:
(500 - 100) / 12 = X
400/12 = X
33,333 = X
Thus, each student club must contribute $ 33.33 in order to meet the fundraising goal.
Answer:
4th answer
Step-by-step explanation:
Im a genius
