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abruzzese [7]
2 years ago
8

Determine whether the ordered pairs are a solution to the system of equations​

Mathematics
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

Step-by-step explanation:o figure out if an ordered pair is a solution to an equation, you could perform a test. Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the y-value you get is the same as the y-value in the ordered pair, then that ordered pair is indeed a solution to the equation.

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John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for the n
musickatia [10]

Answer:

(D) 36%

Step-by-step explanation:

Actual cost of truck = $4500

Down payment = $1500

Money left to be paid = 4500-1500 =  $3000

A = Monthly payments = 350

n = 10

Principal value (P) = 3000

Using formula,

A= \frac{Pr(1+r)^{n}}{(1+r)^{n}-1}

350 =\frac{3000r(1+r)^{10}}{(1+r)^{10}-1}

       = 36% (approx)

Hence (D) is correct.

5 0
3 years ago
I’ll give the Brainliest to whoever answers this question with a reasonable explanation.
SVEN [57.7K]

a) 0-32000
1-30000
2-28000
3-26000
4-24000
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7 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
How many solutions are there to the equation below?
Scrat [10]

Answer:

B

Step-by-step explanation:

6x + 30 + 4x = 10(x+3)

10x + 30 = 10x + 30

0 = 0

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3 years ago
Can someone explain how to factor a number like in the picture I attached? Thank you!
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hey man im sorry i just need points because im strugling

Step-by-step explanation:

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2 years ago
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