Emma divided the trapezoid into two triangles to find the area

*PLEASE ANSWER[MULTIPLE CHOICE] FOR BRIANLIEST* (08.01 MC)

Viktor [21]

Your answer would be (3, 4) is the solution to both lines A and B.

7 0

3 years ago

The volume of a cylinder = ar2h. Use 3.14 for A. What is the volume of this cylinder? You may use the calculator tool in the men

zloy xaker [14]

Answer:

{Height and radius not given}

7 0

2 years ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

3 years ago

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What is the value of x in the diagram below?

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

This is a parallelogram. In parallelogram, opposite sides are equal.

x + 3 = 6

x = 6 - 3

x = 3

4 0

3 years ago

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How can I trust your guys

Zinaida [17]

Answer:

Step-by-step explanation:

you just do, everyone in here needs help so i dont think theres people in here just messing arround, you can trust.

7 0

3 years ago

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Emma divided the trapezoid into two triangles to find the area​

Emma divided the trapezoid into two triangles to find the area