The average rate of change between 1991 and 1996 is 40 million
<h3>How to determine the average rate of change between 1991 and 1996?</h3>
The given parameters are:
Population in 1991 = 1.5 billion
Population in 1996 = 1.7 billion
The average rate of change between 1991 and 1996 is calculated as:
Rate = (1.7 billion -1.5 billion)/(1996 - 1991)
Evaluate
Rate = 40 million
Hence, the average rate of change between 1991 and 1996 is 40 million
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If the length is 7/6 the width w then the perimeter is w + (7/6)w + w + (7/6w)
= 2((7/6)w + w) = 2w + (14/6)w = (26/6)w = (13/3)w.
So the answer is the last one.
Answer:
186.66
Step-by-step explanation:
Answer:
Two adult tickets and 5 student tickets
Step-by-step explanation:
Let a=adult tickets Let s=student tickets
You know that each adult ticket is $9.10 and each student ticket cost $7.75. At the end, it cost $56.95 for both students and adults so the first equation should be 9.10a+7.75s=56.95. To get the second equation, you know that Mrs. Williams purchased 7 tickets in total that were both students and adults. Therefore, the second equation should be a+s=7. The two equations are 9.10a+7.75s=56.95
a+s=7.
Now, use substitution to solve this. I will isolate s from this equation so the new equation should be s=-a+7. Plug in this equation to the other equation, it will look like this 9.10a+7.75(-a+7)=56.95. Simplify this to get 9.10a-7.75a+54.25=56.95. Simplify this again and the equation will become 1.35a=2.70. Then divide 1.35 by each side to get a=2. This Mrs. Williams bought two adult tickets. Plug in 2 into a+s=7, it will look like this (2)+s=7. Simplify this and get s=5. This means Mrs. Williams bought five adult tickets. Therefore she bought 2 adult tickets and 5 student tickets.
Hope this helps
