Answer:
cost of nachos = $3.45
Cost of tacos = $1.5
Step-by-step explanation:
Let
x = cost of nachos
y = cost of tacos
11x + 18y = 64.95 (1)
6x + 15y = 43.20 (2)
Multiply (1) by 6 and (2) by 11 to eliminate x
66x + 108y = 389.70
66x + 165y = 475.20
Subtract to eliminate x
165y - 108y = 475.20 - 389.70
57y = 85.50
y = 85.50/57
y = 1.5
Substitute y = 1.5 to find x
11x + 18y = 64.95 (1)
11x + 18(1.5) = 64.95
11x + 27 = 64.95
11x = 64.95 - 27
11x = 37.95
x = 37.95/11
x = 3.45
cost of nachos = $3.45
Cost of tacos = $1.5
Answer:
c
Step-by-step explanation:
because it times it in six
Answer:
x = 162 cards need to be dealt with
Step-by-step explanation:
Given:
- Estimation of likelyhood of next card to be queen, a king, or an ace:
( 64 - 0.2*x ) / ( 208 - x )
Find:
For what values of x is this likelihood greater than 70%?
Solution:
- Use the likely-hood estimation relation and set up the inequality as follows:
( 64 - 0.2*x ) / ( 208 - x ) > 0.7
( 64 - 0.2*x ) > 0.7*( 208 - x )
64 - 0.2*x > 145.6 - 0.7*x
0.5*x > 81.6
x > 163.2
- It would require 162 cards to be dealt with for the probability of next card being queen, a king, or an ace is greater than 70%
Answer: 33 minutes
Step-by-step explanation:
Hi to answer this question we have to write a proportion
Speed rate = 88 step per minute
Time = 90 minutes
So, the proportion is 88 step/min / 90 minutes
For 33 steps per minutes = 33 / x minutes
88/90 = 33/x
solving for x:
x= 33/ (88/90)
x = 33.75 = 33 minutes.
Feel free to ask for more if needed or if you did not understand something.
Answer: Melanie swam 63 minutes more in second week.
Step-by-step explanation:
Given , Time taken by Melanie in first week to swim = 142 minutes
Combined time taken by her in first two weeks in swimming = 347 minutes
Now , time taken by her in second week = (Combined time of first two week) - (Time taken in first week)
= 347-142 minutes
= 205 minutes
Clearly , 205 > 142 i.e. She swam more in second week than first week./
Difference i= 205-142 = 63
Therefore, Melanie swam 63 minutes more in second week.
