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slamgirl [31]
3 years ago
6

11. Solve for x 3x + 3 − x + (−7) > 6 A. x > 5 B. x > (−5) C. x < 5 D. x > 2.5

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

3x + 3 - x -7 is greater than 6.

2x - 4 is greater than 6.

2x is greater than 10.

x is greater than 5.

Hence, the answer is (A).

Aneli [31]3 years ago
7 0

Answer:

A. x > 5

Step-by-step explanation:

We have been given the inequality;

3x + 3 − x + (−7) > 6

The first step is to collect the like terms;

3x-x+3-7>6

2x-4>6

2x>6+4

2x>10

x>5

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A circle with radius 3 has a sector with a central angle of 60.<br> What is the area of the sector?
CaHeK987 [17]

Answer:

Sector area = (central angle / 360) * PI * radius^2

Sector area = (1/6) * PI * 3^2

Sector area = 9/6 * PI

Sector area = 4.7123889804

Step-by-step explanation:

6 0
3 years ago
2.02b + 4.30 = 2.00b + 6.30
bonufazy [111]

Answer: b = 100

Step-by-step explanation:

simplifying

2.02b + 4.30 = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 6.30 + 2.00b

solving

4.30 + 2.02b = 6.30 + 2.00b

solving for variable 'b'.

move all terms containing b to the left, all other terms to the right.

add '-2.00b' to each side of the equation.

4.30 + 2.02b + -2.00b = 6.30 + 2.00b + -2.00b

combine like terms: 2.02b + -2.00b = 0.02b

4.30 + 0.02b = 6.30 + 2.00b + -2.00b

combine like terms: 2.00b + -2.00b = 0.00

4.30 + 0.02b = 6.30 + 0.00

4.30 + 0.02b = 6.30

add '-4.30' to each side of the equation.

4.30 + -4.30 + 0.02b = 6.30 + -4.30

combine like terms: 4.30 + -4.30 = 0.00

0.00 + 0.02b = 6.30 + -4.30

0.02b = 6.30 + -4.30

combine like terms: 6.30 + -4.30 = 2

0.02b = 2

divide each side by '0.02'.

getting:  b = 100

6 0
3 years ago
use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi
MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd  (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

#SPJ4

5 0
1 year ago
What is the y value in this equation ?X(0)=(-1/3y)+6
snow_lady [41]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
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