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notsponge [240]
3 years ago
7

Mary chooses an integer at random from 1 to 6. What is the probability that the integer she chooses is a prime number?

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0

Answer: 3 out of 6

Step-by-step explanation:

The numbers she choses from are 1-6 therefore its out of 6

The prime numbers before six are two, three, and five.

therefore its 3/6 chance or 1/2 chance she picks a prime number.

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your uncle jim lives in england, where the current exchange rate is 1.64 US dollars for each British pound. Solve for the amount
Talja [164]

Based on the amount of your monthly bill, if you lived in England, your bill to the nearest hundredth is $185.82

<h3>How to find your bill in pound sterling?</h3>

You have a monthly bill of $304.72. If this was also your bill in England id you stayed there, it would need to be converted to pounds. The way to do this is by using the exchange rate.

If each British Pound is $1.64 U.S. Dollar, then the value of your monthly bill if you lived in England is:

= Monthly bill in dollars / Conversion or exchange rate

= 304.72 / 1.64

= $185.82

Find out more on the exchange rate at brainly.com/question/20332320

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7 0
1 year ago
What is 0.08 in 1/10
Paha777 [63]
1/10 of 0.08 is 0.008
4 0
3 years ago
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Please help on this?
Yakvenalex [24]

A. is right

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8 0
3 years ago
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2n + 5 = 35 what is the value of n?
Svet_ta [14]

Answer:

  • 15

Step-by-step explanation:

2n+5=35

2n=35-5

2n=30

n=15

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8 0
3 years ago
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Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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