An atm personal identification number (pin) consists of four digits, each a 0, 1, 2, . . . 8, or 9, in succession.
a. How many different possible pins are there if there are no restrictions on the choice of digits?
Solution: The are total 10 numbers between 0 and 9.
Also there are no restrictions on the choice of digits. Therefore, the possible number of different PINs is:
Therefore, there are 10,000 different possibles PINs.
Please excuse my dear aunt Sally. Parenthesis, exponents, multiplication, division, addition, subtraction.
Answer:
y=1x-8
Step-by-step explanation:
Lets do the same thing we did last time
-3=1(5)+?
-3=5+?
The y intercept is -8
CHECK:
-3=1(5)+-8
-3=5+-8
-3=-3
(0,3)(1,9)
slope = (9 - 3) / (1 - 0) = 6/1 = 6
y = mx + b
slope(m) = 6
use either of ur points...(0,3)...x = 0 and y = 3
now sub and find b, the y int
3 = 6(0) + b
3 = b
ur equation is : y = 6x + 3
for an inequality, a dashed line means there is no equal sign in the problem...and shading above the line means greater then.
so ur inequality is : y > 6x + 3
