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emmainna [20.7K]
3 years ago
14

A bag contains 5 red marbles, 8 white marbles, and 7 blue marbles. You draw 4 marbles out at random, without replacement. What i

s the probability that all the marbles are red?
Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer: 8/7752

Step-by-step explanation:

Since we are told that the bag contains 5 red marbles, 8 white marbles, and 7 blue marbles. The total number fo marbles would be:

= 5 + 8 + 7

= 20 marbles

If 4 marbles out at random, without replacement, the probability that all the marbles are red would be:

= 5/20 × 4/19 × 3/18 × 2/17

= 1/4 × 4/19 × 1/6 × 2/17

= 8/7752

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How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}

Then

Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\

Note that since

F \cap R=\varnothing, Perm(F)\cap Perm(R)\ne \varnothing

But since

B \cap R \ne \varnothing, Perm(B)\cap Perm(R)= \varnothing

and

B \cap F \ne \varnothing , Perm(B)\cap Perm(F)= \varnothing

Since

|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\

where |Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}

and

|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0
2 years ago
Two functions are given below: f(x) and h(x). State the axis of symmetry for each function and explain how to find it.
andrew-mc [135]

Answer:

f(x):

x =  - 4

g(x)

x = 1

Step-by-step explanation:

When a function is of the form:

f(x) = a {(x - h)}^{2}  + k

The equation of the axis of symmetry is

x = h

The given function is

f(x) = 3 {(x + 4)}^{2}  + 1

We can see that h=-4

Hence the equation of axis of symmetry is

x =  - 4

From the graph, the axis of symmetry of h(x) is the vertical line that divides the parabola into two congruent halves.

This line is

x = 1

4 0
3 years ago
Find the length of the third side of each triangle mark
Sedaia [141]

Answer:

I'm going to use the Pythagoras theorem

1. hypotenus²= base²+height²

h²=80²+18²

h²=6400+324

√h²=√6724

hypotenuse= 82

2. 53²=45²+h²

2809=2025+h²

2809-2025=h²

784=h²

√784=√h²

h=28

3. 40²=b²+24²

1600=b²+576

1600-576=b²

√1024=√b²

b= 32

5 0
3 years ago
Mary has 18 marbles. If Tim has 5 times as many marbles as Mary, which number sentence shows how many marbles Tim has?
mariarad [96]

Answer:

A

Step-by-step explanation:

18 x 5 = 90

3 0
3 years ago
Read 2 more answers
Which is the graph of the linear equality 2x-3y<12
WINSTONCH [101]

Answer:

The graph below shows the answer to

2x - 3y < 12

Also shown as

-3y < -2x + 12

Step-by-step explanation:

You can rearrange the inequality by subtracting 2x from both sides to isolate the y.

You now have -3y < 12 -2x

which can be put into the standard linear equation form of

-3y < -2x + 12

Then you divide both sides by -3 to get singular value of y, which is something like

-3/-3y < -2/-3x + 12/-3

which is

y > 2/3x -4

Note: I switched direction of the inequality because you are dividing both sides by a negative value.

7 0
3 years ago
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