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Likurg_2 [28]
2 years ago
8

Can someone explain to me how to remove all the perfect squares ? I’m kind of confused and my teacher is unavailable to help and

my work is already past due :/

Mathematics
1 answer:
mixer [17]2 years ago
4 0

Answer:

b^2√30b

Step-by-step explanation:

√30b^5 - Original

Break down the radical with its factors (factor tree)

√3*2*5*b*b*b*b*b  

See what perfect squares you can take out (Can take out four b terms)  You cant take out any perfect squares involving 30 since there are no perfect squares

b^2√3*2*5*b

b^2√30b

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Let x as the missing segment.

_________________________________

According to the Thales theorem :

\frac{26}{x}  =  \frac{12}{36}  \\

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\frac{26}{x}  =  \frac{1}{3}  \\

Inverse both sides

\frac{x}{26}  =  \frac{3}{1}  \\

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Multiply sides by 26

26 \times  \frac{x}{26}  = 26 \times 3 \\

x = 26 \times 3

x = 78

Thus the missing segment has a measure of 78 .

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