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3 years ago

13

Please help me i need this grade !

2 answers:

Phoenix [80]3 years ago

3 0

Answer:

C

Step-by-step explanation:

(Give me brainliest)

6^2 + 8^2 = ?

? = 100

10^2 = 100

raketka [301]3 years ago

3 0

Answer:

The answer is "The empty square has a side length of 10 and an area of 100 square units"

Step-by-step explanation:

I hope this helps

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What is the equivalent faction to 2/5

AysviL [449]

There are multiple answers, here are some.

4/10
8/15

and so on and so forth, to find these, just multiply each by two, three, and so on and so forth to find more.

Hope this helps!

8 0

3 years ago

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What is the value of c so that -9 and 9 are both solutions of x^2+c=103?

Sladkaya [172]

Answer:

Explanation:

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7 0

3 years ago

What is 345 written as a percent?<br> F. 0.0093%. <br> G. 0.93%<br> H. 9.3%<br> I. 93%

zysi [14]

Answer:

34500%

Step-by-step explanation:

5 0

3 years ago

The area of a trapezium is 800 cm2

svlad2 [7]

Answer:

The distance between the parallel sides is 20cm.

Step-by-step explanation:

Area of a trapezoid:

$A=\frac{a+b}{2}\times h$

where a and b are the 2 bases, and h is the height. The value we're trying to find here is the height.

3 of the 4 variables in this equation are already given:

A = 800

a = 48

b = 32

Just plug those in and solve for h:

$\rightarrow 800=\frac{48+32}{2}\times h\\\rightarrow 800=\frac{80}{2}\times h\\\rightarrow 800=40\times h\\\rightarrow 800\div40=h\\\rightarrow h=20$

5 0

3 years ago

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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago