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Kruka [31]
3 years ago
14

Which land surface would produce greater thermals - a large concrete parking lot, or a large asphalt parking lot? Explain your a

nswer. PLEASE HELP!!
Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0
Asphalt typically gets hotter than concrete since it is black it can absorb 95% of the sun that hits it causing it be be 40 to 60 times hotter than the air temperature around it.
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What is the slope-intercept equation of the line below?
Phoenix [80]

Answer:

D. y = 2x -3

Step-by-step explanation:

The equation of a line in slope-intercept form is

y = mx + b

We need to find m, the slope, and b, the y-intercept.

We can find those two numbers from the graph.

We look in the graph and see that the y-intercept, b, is -3.

Now we have y = mx - 3.

Now we look for the slope. Start at (0, -2). We need to go vertically and horizontally to the next point that is easy to read. We see that point (1, -1) is on a grid intersection making it easy to read, so we will use that point.

Go up 2 units. That is a rise of positive 2. Now go right 1 unit. That is a run of positive 1.

slope = rise/run = 2/1 = 2

m = 2, so now we have

y = 2x - 3

Answer: D. y = 2x -3

3 0
3 years ago
Which equation does the graph of the systems of equations solve?
Lyrx [107]
Solution is x=2 and y=-3

check the slopes since both are in slope int form
y=mx+b
m=slope
b=yint

we see one line has a slope of -2 and yint of 1
another one has a slope of 1/2 and yint of -4

y=-2x+1 and y=1/2x-4
1/2x-4=-2x+1


last one


7 0
3 years ago
What value of x will make AONM similar to ASRQ by
Rashid [163]

Answer:

16 for sure ...

Step-by-step explanation:

16 for sure . which grade question is this ?

8 0
3 years ago
Divide 33 photos into three groups so the ratio is 4 to 7. What will your new ratio be?
ELEN [110]
The answer is 21 i think
7 0
3 years ago
Use the divergence theorem to calculate the surface integral z s ~f d~s ; that is, calculate the ux of ~f across s, where ~f = z
MAXImum [283]
By the divergence theorem,

\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV

where R is the solid whose boundary is S. We have

\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial zx}{\partial z}=1+x

so we set up the volume integral as

\displaystyle\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV=\int_{x=0}^{x=1/a}\int_{y=0}^{y=(1-ax)/b}\int_{z=0}^{z=(1-ax-by)/c}(1+x)\,\mathrm dz\,\mathrm dy\,\mathrm dx
=\dfrac{4a+1}{24a^2bc}
7 0
4 years ago
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