Can anybody help me with this problem in math ? asap . - 20 points !
1 answer:
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Answer:
Answer is 88
Step-by-step explanation:
We have Given function
we have to find f'(x) at x=3 Where f'(x) shows derivative of the given function.
This means we need
f'(3)=?
So By definition of the Derivative that is
so this our definition of derivative of the function
Now We have to find out at x=3, So By putting x =3 in definition ,We get
f'(3)=lim(h---->0)(f(3+h)-f(3))/h
Here lim(h--->0) means limit h approaches to zero(right arrow 0limh→0)
=lim(h---->0)((88(3+h)-77))-(88(3)-77))/h
=lim(h---->0)((264+88h-77)-264+77)/h
=lim(h----->0)(264+88h-77-264+77)/h
now by performing simple arithematic we get result
f'(3) = lim(h---->0)(88h/h)
f('3) = lim(h---->0)(88)
here we use law of the limit we limit of the constant is that constant
lim(h----->0)c=c
so
f'(3)=88
So this our answer