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lilavasa [31]
3 years ago
13

NEED HELP PLEASE!!!!!!!!!!!!!!!

Mathematics
1 answer:
leonid [27]3 years ago
7 0

Answer:

The answer to your question is: 40°

Step-by-step explanation:

Due to the directions, we can know that KL is parallel to GH, then the

∠ FKL ≡ ∠ FGH =  40

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FIND THE VALUE OF X​
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Answer:

By using the rule that the interior angles of any triangle equal 180 we see that:

m<ABC+m<CAB+m<ACB=180°

Therefore,

(2x+15)+(x+10)+(3x+5) = 180°

Now we have an equation and can solve for x:

Combine like terms:

(2x+15)+(x+10)+(3x+5) = 180°

6x+30=180°

6x+30-30=180-30

6x=150

x=25

To check our work just plug in 25 for x in each equation and the sum of those answers should add up to 180:

2x+15

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65

x+10

25+10

35

3x+5

3(25)+5

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80

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x=25 is valid

Step-by-step explanation:

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Step-by-step explanation:

The given function : y=\ln(x(x^2 - 1)^{\frac{1}{2}})

\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}    [\because \ln(ab)=\ln a +\ln b]

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Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

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