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3 years ago

1. How are polynomials added and subtracted?

Mathematics

2 answers:

kramer3 years ago

6 0

Answer:

3: cz

Step-by-step explanation:

MrMuchimi3 years ago

6 0

Answer:

1.) Polynomials are added or subtracted by changing the signs (when needed) and adding/subtracting like terms

2.)161

3.)cz

Step-by-step explanation:

2.) 81^2-80^2

(81+80)(81-80)

161x1

161

3.)ab/c + xy/z = abxy/cz thus, the common denominator is cz

Hope this helps, hope your call goes well :)

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A probability experiment is conducted in which the sample space of the experiment is S 1,2,3,4, 5,6,7,8, 9, 10, 11, 12]. Let eve

Alenkinab [10]

Answer:

$E\ n\ F = \{1, 5, 6,7\}$

$F\ n\ G =\{9\}$

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

$P(F\ U\ G) = \frac{3}{4}$

Step-by-step explanation:

Given

$S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}$

$E = \{1,2, 3, 4, 5, 6,7\}$

$F =\{1,5,6, 7, 8,9\}$

$G = \{9,10, 11, 12\}$

$H = \{2, 3, 4\}$

Solving (5): E and F

Sets of E and F = E n F

$E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}$

List out common elements

$E\ n\ F = \{1, 5, 6,7\}$

They are not mutually exclusive because $n(E\ n\ F) \neq 0$

Solving (6): F and G

Sets of F and G = F n G

$F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}$

List out common elements

$F\ n\ G =\{9\}$

They are not mutually exclusive because $n(F\ n\ G) \neq 0$

Solving (7): F or G and P(F or G)

Sets of F or G = F U G

$F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}$

List all elements without repetition

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

Solving P(F U G)

$P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}$

$n(F\ U\ G) = 9$

$n(S) = 12$

Hence;

$P(F\ U\ G) = \frac{9}{12}$

Divide by 3

$P(F\ U\ G) = \frac{3}{4}$

6 0

3 years ago