Answer:
20
Step-by-step explanation:
Givens
Let child one = x
Let child two = y
Let child three = z
Equations
x^2 + y^2 + z^2 = 100
xy + xz + yz = 150
Solution
There's a trick here. The square of their weights added together is equal (with some modification) to the given conditions. Start by squaring (x+y+z).
(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz
Take out 2 as a common factor from the last three terms.
(x + y + z)^2 = (x^2 + y^2 + z^2+ 2(xy + xz + yz) )
Substitute the given conditions into the equation. (x^2 + y^2 + z^2) = 100 and 2*(xy + xz + yz) = 2 * 150
(x + y + z)^2 = 100 + 2*150
(x + y + z)^2 = 100 + 300
(x + y + z)^2 = 400
Take the square root of both sides.
sqrt(x+y+z)^2 = sqrt(400)
x + y + z = 20
Note
This answer tells you nothing about the values of x y and z. On the other hand it does not ask for the values of x y and z.
ANSWER: 1.8 = 18/10 which is also equal to 4/5
How to convert it:
Multiply both top and bottom by 10:
1 × 10 = 10
1.8 × 10 = 18
To simply it:
18 ÷ 2 = 9
10 ÷ 2 = 5
As an improper fraction, that could also be expressed as: 4/5
I hope this helped! c:
Answer:
HI=1/2*EF
17-3x=1/2*-9x+37
2(17-3x)=-9x+37
34-6x=-9x+37
-6x+9x=37-34
3x=3
x=3/3
x=1
now substitute the value of HI
17-3x
=17-3*1
=17-3
=14
Step-by-step explanation:
Note :HI=1/2*EF because the straight line joining the mid points of two sides of a triangle is parallel to the third side and equal to half of it.
