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grandymaker [24]
2 years ago
11

IS THIS A FUNCTIONS OF NOT I NEED HELP

Mathematics
2 answers:
Wittaler [7]2 years ago
7 0

Answer:

graph 4: yes

graph 5:no

graph 6: no

graph7: no

graph 8: yes

graph 9: no

Step-by-step explanation:

correct me if im wrong

and use vertical line test to figure these put next time :3

Brilliant_brown [7]2 years ago
4 0
1, 3, 5 are functions because they pass the vertical line test
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Find the area and perimeter of the rectangle Length = 5cm Breadth =2cm
avanturin [10]

Answer:

perimeter: 14

Area: 10

Step-by-step explanation:

PERIMETER

2x(L+B) = 2x(5+2) = 2x(7) = 14

AREA

LxB = 5x2 = 10

PLEASE MARK ME BRAINLIEST

5 0
3 years ago
Pls answer this question for ill give brainliest
notka56 [123]

Answer:

BE=15

Step-by-step explanation:

Since E is the center, BE=2x+1

And AC is 6x-12 with E being a midpoint.

Since AC is 2 segments and BE is only 1 then you multiply 2x+1 by 2 so that

you can find x. You multiply 2x+12 by 2 because E is the midpoint so that means ED is the same value as BE

6x-12=4x+2

BD=AC

6x-4x-12=2

2x=2+12

2x=14

x=7

BE= 2x+1

2(7)=14+1=15

7 0
3 years ago
The height of the plant is given by the equation h = 0.50 +4. Rewrite this as a function rule where f(x)is the
mote1985 [20]
The height of the plant is given by the equation h = 0.5d + 4. Rewrite this as a function rule where f(x) is the height, in centimeters, and x is the time, in days. Use the rule to complete the table, and then use the drawing tools to create the graph representing this relationship.
6 0
3 years ago
87+25<br><img src="https://tex.z-dn.net/?f=12%20%2B%2010%20%20" id="TexFormula1" title="12 + 10 " alt="12 + 10 " align="absmid
Butoxors [25]

Answer:

Seriously?

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3 0
3 years ago
Can someone plz help me find the area for this composite figure plzzzz I beg u
Anarel [89]

S_1 = \frac{a+b}{2}h = \frac{7+9}{2}*5=\frac{18*5}{2}= 9 * 5 = 45~m^2

S_\triangle = \frac{ab}{2} = \frac{5*9}{2} = \frac{45}{2} = 22,5~m^2

S = S_1 + S_\triangle = 45 + 22,5 = 67,5~m^2

Answer: 67,5 m².

5 0
3 years ago
Read 2 more answers
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