The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago

Timothy made 60 quarts of cider he poured the cider into containers. Each container holds 4/11 of a quart. How many containers d

Dahasolnce [82]

60 / (4/11) =
60 * 11/4 =
660/4 =
165 containers

7 0

3 years ago

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Two sides of a triangle are 8cm and 12cm. Which of the following CANNOT be the measure of the third side,

blondinia [14]

Answer:

4 cannot be the measure of the third side. This is because of the Triangle Inequality Theorem, which states that the sum of two sides of a triangle must be greater than the third side (A+B>C, A+C>B, B+C>A) In this example, if side C were 4, side C (4) plus side A (8) would be 12. Since side B is 12, and 12 cannot be greater than 12, 4 would not work.

Answer=8

Step-by-step explanation:

7 0

4 years ago

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What is the vertex of the graph of the function below? y = x2 + 6x + 5

Aleksandr-060686 [28]

Answer:

(-3,-4)

If you have a chart with the coordinates in it, it will be in the middle of alike coordinates.

7 0

3 years ago