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3 years ago

Can someone please help? U get points just from typing and I would really appreciate it.

Mathematics

2 answers:

suter [353]3 years ago

6 0

Answer:

Step-by-step explanation:

Consecutive numbers are directly next to each other on the number line, so B is already out of the question. Add each pair together to see which one is 131.

seropon [69]3 years ago

6 0

Answer:

C. 65 and 66

Step-by-step explanation:

Let x be first number

Then x + 1 be next number

x + (x + 1) = 131

2x + 1 = 131

2x = 130

x = 65

x + 1 = 66

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Ayo what this?????????????? My teacher tripping

Hunter-Best [27]

He/she really tripping but maybe try simplifying them ?

8 0

3 years ago

8. Divide: (6x² - 4x)+2x<br>A. 3x - 4x<br>B. 3x - 2x<br>C. 6x-2<br>D. 3x - 2

kompoz [17]

Answer:

3x-2

Step-by-step explanation:

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3 years ago

Find the 7th term in the sequence -10,-6,-2,2...

jeyben [28]

1st term = -10

2nd term = -6

3rd term = -2

4th term = 2

5th term = 6

6th term = 10

7th term = 14

The reason how I got 14 for the 7th term is because, i added 4 to each term.

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is 5,683 divided by 8

salantis [7]

Answer:710.375‬

Step-by-step explanation:

7 0

3 years ago

Use the relative frequency approach to estimate the probability of the event. In a certain class of students, there are 8 boys f

In-s [12.5K]

Answer:

$P\text{Student will be from Kenilworth}\approx 0.256$

Step-by-step explanation:

We have been given that that there are 8 boys from Wilmette, 5 girls from Kenilworth, 9 girls from Wilmette, 5 boys from Glencoe, 5 boys from Kenilworth and 7 girls from Glenoce.

The total number of students from Kenilworth is 5 boys plus 5 girls that is 10 students.

The total number of students in the class would be $8+5+9+5+5+7=39$

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$P\text{Student will be from Kenilworth}=\frac{\text{Number of student from Kenilworth}}{\text{Total number of students}}$

$P\text{Student will be from Kenilworth}=\frac{10}{39}$

$P\text{Student will be from Kenilworth}=0.2564102564$

$P\text{Student will be from Kenilworth}\approx 0.256$

Therefore, the probability, that the student will be from Kenilworth, is approximately 0.256.

7 0

3 years ago