1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleks04 [339]
3 years ago
8

Select all values equivalent to -10/7 -10/-7 -3 1/7 1 3/7 - -10/-7 -1 3/7

Mathematics
1 answer:
Kitty [74]3 years ago
5 0
We know that

case 1) -10/-7-----> 10/7-------> is not <span>equivalent to -10/7

case 2) </span>-3 1/7----> (-3*7+1)/7----> -20/7 ------> is not equivalent to -10/7

case 3) 1 3/7-----> (1*7+3)/7----> 10/7 ------> is not equivalent to -10/7

case 4) - -10/-7---> +10/-7----> -10/7------>  is equivalent to -10/7

case 5) -1 3/7----> (-1*7+3)/7----> -4/7 ------> is not equivalent to -10/7

the answer is
- -10/-7

You might be interested in
-6x+6y=6<br> - 6x+3y=-12 also steps on how to solve it
Masja [62]

Answer:

x=5, y=6. (5, 6).

Step-by-step explanation:

-6x+6y=6

-6x+3y=-12

---------------

simplify -6x+6y=6 into -x+y=1 and y=1-(-x)=1+x

-6x+3(1+x)=-12

-6x+3+3x=-12

-3x=-12-3

-3x=-15

3x=15

x=15/3

x=5

-6(5)+6y=6

-30+6y=6

6y=6-(-30)

6y=6+30

6y=36

y=36/6

y=6

3 0
3 years ago
What numbers added together equal -8
aliya0001 [1]

Answer:

-6 and -2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For what value of k, the following pair of linear equations has unique solution
riadik2000 [5.3K]

Answer:

uv UC uh uh uh uh uh uh uh all tardy txt tch tch addressed to you and your family a very happy and prosperous new year and I have to go go go go go go go go go go go go in to comes to that and return to me and I will pick ⚒️⛏️ me know if you have u I love you too and miss you too babe I love it ❤️ me know when you're ready tomorrow morning to get the money to you and your team for the impostor

Step-by-step explanation:

gucci figure ucc txt ucc p on ohh I thought you were going to be a little late to the party but I love you and I thought I tttty me know if you need anything else from me please let me know if you need anything else from me please let's do that you have a great holiday season and a few others are not going me

8 0
3 years ago
A new technology for the production of integrated circuits is being mastered. The technology will be rejected if the percentage
max2010maxim [7]

Answer:

5901

Step-by-step explanation:

The margin of error is the critical value times the standard error.

ME = CV × SE

For α = 0.05, the critical value is z = 1.96.

The standard error of a proportion is √(pq/n).  Given p = 0.04, then q = 1−p = 0.96.

The margin of error is 0.5% or 0.005.

Plugging in:

0.005 = 1.96 √(0.04 × 0.96 / n)

n ≈ 5901

8 0
3 years ago
Dustin needed 0.80 meter of fabric to make a pillow. The fabric cost $1.50 per meter. How much did Dustin pay for 0.80 meter of
aliina [53]

Given parameters:

Length of fabric needed to make a pillow = 0.8m

Cost of fabric per meter = $1.5

Unknown:

Cost of the 0.8m fabric  = ?

Solution:

  The cost of the fabric  = cost per meter x length of fabric

   Input the parameters and solve;

       Cost of the fabric  = 0. 8 x 1.5 = $1.2

Dustin will have to $1.2 for the fabric

5 0
4 years ago
Other questions:
  • How can investors receive compounding returns?
    7·2 answers
  • Here’s another one :)))!!
    13·1 answer
  • Two intersecting lines will form how many pairs of congruent angles?
    14·1 answer
  • Solve for x.<br> 2x^2+12x+11-(x+4)^2
    7·1 answer
  • Is 2^7 the same as 2 x 7? Why or why not?
    10·2 answers
  • Solve for x <br> 8 + x/3 = 15
    6·2 answers
  • HELP PLZ WILL MARK YOU BRAINLIEST
    8·1 answer
  • I WILL GIVE U BRIANLIEST THING!!!
    10·2 answers
  • Gerri's garden is 1,270 centimeters around the edges. How many meters of fencing material does she need to enclose her garden?​
    15·1 answer
  • Can someone helpppp please I’m struggling!!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!