Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1
Ivan
Answer:
0.6 probability that 
Step-by-step explanation:
The probability distribution is given in the table.
Probability that x is between -2 and 2.
Between -2 and 2, inclusive, we have -2, 0 and 2. So
From the table:
. So
0.6 probability that
Answer:
3,4 for cups of hot cocoa
4 for marshmallows
Step-by-step explanation:
dfggdr
Answer:
256 in²
Step-by-step explanation:
g(x) = x - 3 = 0
g(x) = x = 3
f(x) = 2x^3 + x - 4
f(3) = 2(3)^3 + 3 - 4
f(3) = 2(27) - 1
f(3) = 54 - 1
f(3) = 53
The remainder when f(x) is divided by x - 3 is <u>53</u>.
