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lesya [120]
3 years ago
7

A, B , and C are collinear points: B is between A and C. If AB = 36, BC = 5x - 9 , and AC = 54 , find x

Mathematics
1 answer:
balandron [24]3 years ago
4 0

9514 1404 393

Answer:

  x = 5.4

Step-by-step explanation:

The segment sum theorem tells you ...

  AB +BC = AC

  36 +(5x -9) = 54

  5x = 27 . . . . . . . . . . . subtract 27 from both sides

  x = 5.4 . . . . . . . . . . divide by 5

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Imagine the graph for the relation 4x-5y+20 = 0.<br> What would be its slope?
muminat
4x - 5y + 20 = 0
<u>             - 20  - 20</u>
        4x - 5y = -20
 4x - 4x - 5y = -20 - 4x
              -5y = -20 - 4x
              <u>-5y</u> = <u>-4x - 20</u>
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The slope would be ⁴/₅.
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Find the distance from P to l.
ki77a [65]
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Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}
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Kitty [74]

Answer:

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Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

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The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
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