Answer:
the Answer is 14=5+2^(3-x)
Step-by-step explanation:
Answer:
(-19, 55)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -3x - 2
5x + 2y = 15
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 5x + 2(-3x - 2) = 15
- Distribute 2: 5x - 6x - 4 = 15
- Combine like terms: -x - 4 = 15
- Isolate <em>x</em> term: -x = 19
- Isolate <em>x</em>: x = -19
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3x - 2
- Substitute in <em>x</em>: y = -3(-19) - 2
- Multiply: y = 57 - 2
- Subtract: y = 55
(i) I used distributive property to get the x’s and y’s out of parentheses. I then combined like-terms to simplify until I could do no more. That is your final answer for (i) is -3x - 12y
(ii) This one is similar to the first one, just with no parentheses. I combined like terms again until not like terms were left. Your final answer for (ii) is -3k -2 -2n
(iii) I started by dividing 15 by 3 and got 5, and because the 15 had an x to it, you get 5x. I then moved onto the next term, 9. 9 divided by 3, to get 3. Your final answer for (iii) is 5x + 3
The answer this problem is -247
Answer: D
Step-by-step explanation:
dim A=(a,b), dim B=(c,d), in order to multiply, c=b
1) dim A=(1,2) , dim B=(1,2) but 2≠1
2) dim A=(2,1) , dim B=(2,2) but 1≠2
3) dim A=(2,2) , dim B=(1,2) but 2≠1
4) dim A=(2,1) , dim B=(1,2) 1=1: result (2,2)
