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romanna [79]
3 years ago
8

The cost of producing x hundred items is given by the equation C(x) = x2 – 3x + 7 and the revenue generated from sales of x hund

red units is given by the equation R(x) = –x2 + 21x – 33. What values of x will the company break even?
Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

At x = 2 and 10.

Step-by-step explanation:

Given : The cost of producing x hundred items is given by the equation C(x) = x^2-3x + 7

The revenue generated from sales of x hundred units is given by the equation R(x) = -x^2 + 21x-33

To Find :What values of x will the company break even?

Solution:

Cost function : C(x) = x^2-3x + 7

Revenue function : R(x) = -x^2 + 21x-33

Now to find the company break even :

-x^2 + 21x-33= x^2-3x + 7

24x= 2x^2+40

12x= x^2+20

x^2-12x+20=0

x^2-10x-2x+20=0

x(x-10)-2(x-10)=0

(x-2)(x-10)=0

So, x = 2,10

Hence the company break even at x = 2 and 10.

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John had 2⁄3 of his homework complete, Sarah had 5⁄10, Alex 7⁄8, and Michelle 1⁄2. Who completed the most of the homework assign
yuradex [85]
Hey there!

So, when finding who completed more, we would want to find the lowest denominator, but also, we would have to compare it with the numerator.

John: He completed 2/3, which is basically almost done.

Sarah: She only completed (half) of her homework.

Alex: He only did 7/8

Michelle: He/she only did 1/2, which is only half.

So, from looking at these fractions above, Michelle and Sarah are out.

We would just have to determine, which is finished more, John or Alex.

John had 2/3 & Alex 7/8

So, by comparing them both, 7/8 would be greater because the smaller the denominator is, and the closer that the numerator is to the denominator, this would mean that the homework is almost finished.

Your correct answer is Alex, he has completed more.

Hope this helps you!
4 0
3 years ago
Factorize completely the expression(h+2k)²+4k²-h²​
julsineya [31]

The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

From the question,

We are to factorize the expression (h+2k)²+4k²-h²​ completely

The expression can be factorized as shown below

(h+2k)²+4k²-h²​ becomes

(h+2k)² + 2²k²-h²​

(h+2k)² + (2k)²-h²​

Using difference of two squares

The expression (2k)²-h²​ = (2k+h)(2k-h)

Then,

(h+2k)² + (2k)²-h²​ becomes

(h+2k)² + (2k +h)(2k-h)

This can be written as

(h+2k)² + (h +2k)(2k-h)

Now,

Factorizing, we get

(h +2k)[(h+2k) + (2k-h)]

Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]

Learn more here:brainly.com/question/12486387

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