Answer:
X = 16 cm
Step-by-step explanation:
Pythagoras law is :
20^2 = X^2 + 12^2
400 = X^2 +144
400 - 144 = x^2
256 = x^2
x = ( 256 ) ^1/2
X=16
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer:
A. The situation is discrete B. i. { x : 0 ≤ x ≤ 6; x ∈ Z} ii. { C = 5x : 0 ≤ C ≤ 30; C ∈ Z}
Step-by-step explanation:
A. The situation is discrete since we have integral values for the amount paid per mile walked. The amount per mile is $5 and is only paid if a complete mile is walked. So, it is a discrete situation.
B. i. Since 0 miles represents 0 distance and the student walks a maximum of 6 miles, let x represent the distance walked. So the domain is 0 ≤ x ≤ 6 where x ∈ Z where Z represent integers.
{ x : 0 ≤ x ≤ 6; x ∈ Z}
ii. Since at 0 miles the amount earned is 0 miles × $5 per mile = $ 0 and at the maximum distance of 6 miles, the amount earned is 6 miles × $5 per mile = $ 30, let C represent the amount donated in dollars. So the range is 0 ≤ C ≤ $ 30 where C = 5x.
{ C = 5x : 0 ≤ C ≤ 30; C ∈ Z}
Answer: x=3.16m
Step-by-step explanation:
The condition for destructive interference is given by:
∆r = r1 - r2 = (m + 0.5)lamda
Where
Lamda = speed/frequency
= 343/260 = 1.32m
r1. = x
r2 = 2.50m
Then;
X - 2.5 = (m + 0.5)v/f
X - 2.5 = (m + 0.5)1.32
For m = 0 i.e at maximum destructive interference
x = 3.16m
Answer:
x + y ≥ 3
x + y ≤ 3
Step-by-step explanation:
In the picture attached, the problem is shown.
The solution to the system:
x + y ≥ 3
x + y ≤ 3
is the line x + y = 3
In order to get a solution to a system of inequalities that is a line, we need the same equation on the left (here, x + y), the same constant on the right (here, 3), and the ≥ sign in one inequality and the sign ≤ in the other one.
