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ale4655 [162]
3 years ago
7

Abi has a bag containing black counters and white counters. The ratio of

Mathematics
1 answer:
telo118 [61]3 years ago
7 0

Answer:

1

Step-by-step explanation:

the probability is 1 because the ration of black to white is 1 to 2 so i guess she has 1 chance that it is black

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Multiply (1.2 x 10^28) write it in scientific notation
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1.2e28 that what i got 
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3 years ago
PLEASE PLEASE ANSWER!
muminat

The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

AC^2+4^2=8^2

AC^2=64-16

AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

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Draw a right triangle.

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Arctangent (tan^-1) can be used to find theta.

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I hate school do you guy?
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Answer:every one hates school :(

Step-by-step explanation:

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