Well first lets find the ROC (rate of change) in the sets of data.
1990 -> 134
2000 -> 139
so lets find the difference from the years given
2000-1990=10 so there is a 10 year gab
139-134=5 so there is a 5 million increase in the population
so divide 10 by 5 which gives us 2, so every year there is a 2 million increase in the population. so from 2000 to 2014 there is 14 years, so
14 x 2= 28, then add that to the latest population data
139+28=167
so the population in 2014 would be 167 million
Hope this helped!!
Answer:
5x+4y=85-
Slope = -2.500/2.000 = -1.250
x-intercept = 85/5 = 17
y-intercept = 85/4 = 21.25000
2x+3y=41-
Slope = -1.333/2.000 = -0.667
x-intercept = 41/2 = 20.50000
y-intercept = 41/3 = 13.66667
Answer:
the common ratio is 0.98.
Step-by-step explanation:
A fish population in a lake decreases by 2% each year. We are asked to find the common ratio.
The decrease of population of fish 2% annually means the population becomes next year 100% - 2% = 98%
Therefore, the common ratio would be 98%. Upon converting 98 percent to a decimal we will get,
98% = 
Therefore, the common ratio or decay factor is 0.98.
Answer:
- equivalent rate: 7.186%
- compounded 16 times
Step-by-step explanation:
The equivalent interest rate is the rate that would have to be applied so it would earn the same amount in 1 year. It is computed from ...
requiv = (1 +r/n)^n -1
requiv = (1 +0.07/4)^4 -1 ≈ 7.186%
__
"Compounded quarterly" means interest is compounded 4 times per year. In 4 years, it will be compounded 4·4 = 16 times.
__
The balance in the account after 4 years is ...
$600·(1 +.07/4)^(4·4) ≈ $791.96
