Answer:
0.46666667
Step-by-step explanation:
https://thefractioncalculator.com/FractionAsaDecimal/What-is-7/15-as-a-decimal.html
You would need to come in 583.6 or 584 times
3/5x + 5 = 4/5
3/5x + 5 (-5) = 4/5 (-5)
3/5x = -4 1/5
3/5x/(5/3) = -4 1/5(/)(5/3)
x = (- 21/5)/ (5/3)
x = -21/5 x (3/5) (flip the signs by flipping the second fraction and the divide to a multiply)
x = -21/5 x 3/5
x = -63/25 or x = - 2.52
hope this helps
We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
<h3>Workdone in stretching natural length</h3>
Question Parameters:
- A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
- Stretching it from its natural length to 9 inches beyond its natural length
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
![W=8[x^2]^{3/4}_{0}](https://tex.z-dn.net/?f=W%3D8%5Bx%5E2%5D%5E%7B3%2F4%7D_%7B0%7D)
W=9/2lbft
For more information on Length visit
brainly.com/question/2096451