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Zarrin [17]
3 years ago
13

I’m late on hw and need it done now or I repeat grade

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Make 7 a fraction

Flip the second fraction

Multiply

Simplify

7/1 x 4/3=28/3=9 1/3

4vir4ik [10]3 years ago
7 0
<h3>Ever heard of KCF?</h3>

(Keep Change Flip)

<u>Keep 7, change dividing to multiplying, and change 3/4 to 4/3.</u>

7 x (4/3)

7x4=28

<h3><u> 28 </u></h3><h3>  3</h3><h3 /><h3>7÷3/4 = 9.3 (It's a repeating decimal, so put a vinculum over the 3)</h3><h3 /><h3 /><h3 />

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In a recent pizza-eating contest, Alfonso ate 1 3/8 pizzas, Della ate 1 3/10 and jack ate 1 4/9. Which person won?
Marat540 [252]

alfonso won the pizza contest

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3 years ago
Whats 7/15 as a decimal
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Answer:

0.46666667

Step-by-step explanation:

https://thefractioncalculator.com/FractionAsaDecimal/What-is-7/15-as-a-decimal.html

3 0
3 years ago
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5 0
3 years ago
Solve for X.<br> 3/5x+5=4/5
stich3 [128]
3/5x + 5 = 4/5

3/5x + 5 (-5) = 4/5 (-5)

3/5x = -4 1/5

3/5x/(5/3) = -4 1/5(/)(5/3)

x = (- 21/5)/ (5/3)
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x = -21/5 x 3/5
x = -63/25 or x = - 2.52



hope this helps
3 0
4 years ago
Read 2 more answers
A force of 128 lb is required to hold a spring stretched 2 ft beyond its natural length. How much work W is done in stretching i
Agata [3.3K]

We have that the  workdone in stretching natural length to is mathematically given as

W=9/2lbft

<h3>Workdone in stretching natural length</h3>

Question Parameters:

  • A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
  • Stretching it from its natural length to 9 inches beyond its natural length

Generally the Hookes equation for the Force   is mathematically given as

F=Kx

Where

3.2lb=2ft*k

Thereofore

k=16

Force becomes

f=kx

f=16x

Hence

W=8[x^2]^{3/4}_{0}

W=9/2lbft

For more information on Length visit

brainly.com/question/2096451

6 0
2 years ago
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