X=3
Explanation:
A straight line equals 180°, and they give you the one angle of 56°, so you know 56+ the other equation has to equal 180
56+4x+112=180
168+4x=180
Subtract 168 from both sides
4x=12
Divide 4 from both sides
X=3
You can check by filling it in.
56+4*3+112=
12+56+112=180
To find one year, here's the equation:
5000 + 0.06(5000)
For 10 years:
5000 + 10(0.06(5000))
Multiply:
5000 + 0.6(5000)
We can make it smaller:
1.6(5000) = 8000
You can make $8000
9514 1404 393
Answer:
Step-by-step explanation:
Let J and M represent the current ages of Jacob and his Mother.
<u>currently</u>:
M = 3 +9J
<u>in 11 years</u>:
M+11 = 5 +3(J+11)
Using the first equation to substitute for M in the second, we have ...
(3 +9J) +11 = 5 +3(J +11) . . . . . substitute for M
9J +14 = 3J +38 . . . . . . simplify
6J + 24 . . . . . . . . . . subtract 3J+14
J = 4 . . . . . . . . . . divide by 6
M = 3 +9(4) = 39
Jacob is 4 and his mother is 39.
Answer:
What are the options?
Step-by-step explanation:
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.
So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:
<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>
where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.
