Answer:
<h2>
![(g \: \circ \: f)(0) = 17](https://tex.z-dn.net/?f=%28g%20%5C%3A%20%5Ccirc%20%5C%3A%20f%29%280%29%20%3D%2017)
</h2>
Step-by-step explanation:
f(x) = 2x + 4
g(x) = 4x² + 1
In order to find (g ∘ f)(0) we must first find
(g ° f )(x)
To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)
That's
<h3>
![(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\ = 4(4 {x}^{2} + 16x + 16) + 1 \\ = {16x}^{2} + 64x + 16 + 1](https://tex.z-dn.net/?f=%28g%20%5C%3A%20%5Ccirc%20%5C%3A%20f%29%28x%29%20%3D%204%28%20%28%7B2x%20%2B%204%7D%29%5E%7B2%7D%20%29%20%2B%201%20%5C%5C%20%20%3D%204%284%20%7Bx%7D%5E%7B2%7D%20%20%2B%2016x%20%2B%2016%29%20%2B%201%20%5C%5C%20%20%3D%20%20%7B16x%7D%5E%7B2%7D%20%20%2B%2064x%20%2B%2016%20%2B%201)
</h3>
We have
<h3>
![(g \: \circ \: f)(x) = {16x}^{2} + 64x + 17 \\](https://tex.z-dn.net/?f=%28g%20%5C%3A%20%5Ccirc%20%5C%3A%20f%29%28x%29%20%3D%20%20%7B16x%7D%5E%7B2%7D%20%20%2B%2064x%20%2B%2017%20%5C%5C%20)
</h3>
Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)
We have
<h3>
![(g \: \circ \: f)(0) = 16( {0})^{2} + 64(0) + 17 \\](https://tex.z-dn.net/?f=%28g%20%5C%3A%20%5Ccirc%20%5C%3A%20f%29%280%29%20%3D%2016%28%20%7B0%7D%29%5E%7B2%7D%20%20%2B%2064%280%29%20%2B%2017%20%5C%5C%20)
</h3>
We have the final answer as
<h3>
![(g \: \circ \: f)(0) = 17](https://tex.z-dn.net/?f=%28g%20%5C%3A%20%5Ccirc%20%5C%3A%20f%29%280%29%20%3D%2017)
</h3>
Hope this helps you
Answer: ½ x + 6 < 34 ; x < 56
Step-by-step explanation:
- Subtract 6 on both sides. ½ x < 28.
- Divide ½ on both sides. x < 56.
Let's begin by breaking each number down into its prime factors: 4 = 2 x 2 5 = 5 6 = 2 x 3 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4, 5, and 6 by multiplying all common and unique prime factors of each number: common prime factors: 2 unique prime factors: 2,5,3 LCM = 2 x 2 x 5 x 3 = 60 Next, let's determine how many times 60 goes into 10,000 (excluding remainder): 10,000/60 = 166 and 2/3 Multiples of ALL 3 numbers (4,5,6) = 166 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4 and 5 by multiplying all common and unique prime factors of each number: common prime factors: none
unique prime factors: 2 x 2 x 5
LCM = 2 x 2 x 5 = 20 Next, let's determine how many times 20 goes into 10,000:
10,000/20 = 500
Multiples of BOTH numbers (4 and 5) = 500 Finally, let's subtract the multiples of ALL three numbers (4,5,6) from the multiples of BOTH numbers (4 and 5) to get our answer: Multiples of ONLY numbers 4 and 5 (excluding 6): 500 - 166 = <span>334</span>
The equation would be 14x+2=t......
Breakdown: 14 times X (the number of tickets purchased) plus the one time processing fee of 2 dollars will equal T (the total)
Answer:
3.14159, this is π
Followed by 2-6-5-3-5-8-9
Circumference over diameter
7-9, then 3-2-3
OMG! Can't you see?
8-4-6-2-6-4-3
And now we're on a spree
38 and 32, now we're blue
Oh, who knew?
7, 950 and then a two
88 and 41, so much fun
Now a run
9-7-1-6-9-3-9-9
Then 3-7, 51
Half way done!
0-5-8, now don't be late
2-0-9, where's the wine?
7-4, it's on the floor
Then 9-4-4-5-9
2-3-0, we gotta go
7-8, we can't wait
1-6-4-0-6-2-8
We're almost near the end, keep going
62, we're getting through
0-8-9-9, on time
8-6-2-8-0-3-4
There's only a few more!
8-2, then 5-3
42, 11, 7-0 and 67
We're done! Was that fun?
Learning random digits
So that you can brag to your friends
Step-by-step explanation: