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3 years ago

Pls help me i need it

Mathematics

1 answer:

Delvig [45]3 years ago

4 0

Answer:

13=x

Step-by-step explanation:

Side-spliting theorem

21/(x-4)=14/6

cross multiply

21*6=14*(x-4)

distribute 14

126=14x-56

add 56 to both sides

126+56=14x-56+56

leaving you with

182=14x

Divide both sides by 14 to get x by itself

182/14=14x/14

13=x

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A study of the effect of smoking on sleep patterns is conducted. The measure observed is the time, in minutes, that it takes to

nordsb [41]

Answer:

The group that has greater value of relative dispersion is the smokers group, as the coefficient of variationof their data is bigger than the coefficient of variation of the non-smokers group data.

CV smokers: 0.387

CV non-smokers: 0.234

Step-by-step explanation:

We will calculate the relative dispersion of each data set with its coefficient of variation (ratio of the standard deviation to the arithmetic mean).

Then, first we calculate the mean and standard deviation for the smokers data:

Mean: 43.7

Standard deviation: 286.5

$M_s=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_s=\dfrac{1}{12}(69.3+56+22.1+47.6+53.2+. . .+13.8)\\\\\\M_s=\dfrac{524.4}{12}\\\\\\M_s=43.7\\\\\\s_s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_s)^2\\\\\\s_s=\dfrac{1}{11}((69.3-43.7)^2+. . . +(13.8-43.7)^2)\\\\\\s_s=\dfrac{3152}{11}\\\\\\s_s=286.5\\\\\\$

The mean and standard deviation for the non-smokers is:

Mean: 30.3

Standard deviation: 50.9

$M_n=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_n=\dfrac{1}{15}(28.6+25.1+26.4+34.9+28.8+. . .+13.9)\\\\\\M_n=\dfrac{453.8}{15}\\\\\\M_n=30.3\\\\\\s_n=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_n)^2\\\\\\s_n=\dfrac{1}{14}((28.6-30.3)^2+. . . +(13.9-30.3)^2)\\\\\\s_n=\dfrac{713.3}{14}\\\\\\s_n=50.9\\\\\\$

Now, we can calculate the coefficient of variation:

CV smokers:

$CV_s=\dfrac{s_s}{M_s}=\dfrac{16.9}{43.7}=0.387$

CV non-smokers:

$CV_n=\dfrac{s_n}{M_n}=\dfrac{7.1}{30.3}=0.234$

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4 years ago

Pls help me i need it​

Pls help me i need it