So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
Answer:
23
Step-by-step explanation:
Use the hint to solve!
New equation would be 49 = 26 + h.
49 - 26 = 23.
Holly has 23 barrettes.
<h3>
Answer: 17</h3>
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Explanation:
We'll start things off by computing the inner function u(2)
Plug x = 2 into the u(x) function
u(x) = -x-1
u(2) = -2-1
u(2) = -3
This tells us that w(u(2)) is the same as w(-3). I replaced u(2) with -3.
We'll plug x = -3 into the w(x) function
w(x) = 2x^2-1
w(-3) = 2(-3)^2 - 1
w(-3) = 2(9) - 1
w(-3) = 18-1
w(-3) = 17
Therefore, w(u(2)) = 17
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Here's a slightly different approach:
Let's find what w(u(x)) is in general
w(x) = 2x^2 - 1
w(u(x)) = 2(u(x))^2 - 1
w(u(x)) = 2(-x-1)^2 - 1
Then we can plug in x = 2
w(u(x)) = 2(-x-1)^2 - 1
w(u(2)) = 2(-2-1)^2 - 1
w(u(2)) = 2(-3)^2 - 1
w(u(2)) = 2(9) - 1
w(u(2)) = 18 - 1
w(u(2)) = 17
The answer is 11 :) hope this helps
Scale factor: f=0.5
AB=2.2
LM=?
LM=f x AB=0.5 x 2.2 →LM=1.1
The length of LM is 1.1
