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Doss [256]
3 years ago
13

GET T-F OUT OF HERE MATE

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

ok mate

Step-by-step explanation:

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Benito wrote the equations shown about the figure. Explain Benito’s errors.
Whitepunk [10]

Answer:

  • Benito's error was stating that the correspongind sides and angles are equal (=) instead of stating that they are congurent (≅).

Explanation:

In geometry two different figures (segments, angles, polygons ,...) are not said to be equal but congruent.

Congruent means that they have the same measure but not that they are equal in other senses.

The use of equal is applied to numbers or variables),so you can tell x = 2, 3 = 3, A = πr², but you should not say segment AB is equal to segment BC. Instead you say segment AB ≅ segment BC, which is segment AB is congruent to segment BC.

Of course, you still can use the word equal (symbol =) if you state that you are talking about measures.

This also can help you

  • Correct: segment  AB ≅ segment BC  
  • Correct: legth of segment AB = length of segment BC
  • Incorrect: segment AB = segment BC

Segment AB and segment BC are not equal because they are two different segments. They are congruent because they have the same length.

Note: the bars shown over the letters AB, BC, AD, DC, mean segment.

6 0
4 years ago
write the equation and find the values of x. round side lengths to the nearest tenth and angle measures to the nearest degree ​
Vlad1618 [11]

Answer:

  • x = 44°

Step-by-step explanation:

<u>Equation</u>:

  • cos x = 15/21
  • cos x = 0.714
  • x = arccos 0.714
  • x = 44° (rounded to the nearest degree)
3 0
3 years ago
Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.
makkiz [27]
Can't be done without knowing what f is...

But I can tell you that the average value of f is given by

\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}

At the very least, we can compute the denominator, which is just the area of R. You have

\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12

so the average value will be

2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy
4 0
4 years ago
HELP! Evaluate. Make sure to show your work and provide complete geometric explanations.
noname [10]

Answer: lol thats rough gummy bear

Step-by-step explanation:

6 0
3 years ago
I need help with this question! ​
vivado [14]

Answer:

free points :)

Step-by-step explanation:

:)

3 0
3 years ago
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