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3 years ago

A farm is 9 in wide and 6 in tall. if it is redused to a width of 3 in then how tall will it be

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

It will still be 6 units high. Even if the width is reduced, that does not effect the height of the farm.

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Can someone please answer?

Whitepunk [10]

Answer:

Step-by-step explanation:

another way to express 52+24 is 4(13+6)

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2 years ago

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Find a number smaller than 19 that has more factors than the numbers 19 21 23 25

Pepsi [2]

18 has more factors than all of those numbers.

1, 2, 3, 6, 9, 18 are all the factors of 18.

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3 years ago

A jeweler orders necklaces from a website that offers $6 shipping for any-size order. Each necklace costs $7. The jeweler wants

Furkat [3]

Answer:

c = $7n + $6

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3 years ago

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Esther has a farm.

Gnesinka [82]

Here, we are required bro determine how many worker Esther needs to employ to pick the same 600kg of onions in 3 hours as compared to 4 hours from last year.

This year, she needs to employ 32 workers to pick a total of 600kg of onions in 3 hours.

According to the data given, the total quantity of onions to be picked still remains 600 kg as from last year, only that she needs it done in 3 hours now.

Therefore,

Since 24 workers finished the work in 4 hours,
This means that 96 workers are needed to finish the work in 1 hour( from 24×4 = 96).

Therefore, since the work needs to be done in 3 hours this year, This means that it can be shared between X no. of workers.

Where X = 96/3= 32

Therefore, this year she needs to employ 32 workers to pick a total of 600kg of onions in 3 hours.

Read more:

brainly.com/question/3796978

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2 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago