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shusha [124]
3 years ago
10

PLZ HELP ASAP MARKIN BRAINIEST !!!

Mathematics
1 answer:
zzz [600]3 years ago
3 0
Put a dot on -7 and -1 so the slope is 3 over 2x for the first inequality and the y is -1 do rise over run for each the slope for second is 1 over 1 put a dot for both on y axis (:
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Help on this please, i dont get this problem.
Ahat [919]

Answer:

<h2>A = 37 cm²</h2>

Step-by-step explanation:

Look at the picture.

We have two rectangles:

15cm × 2cm and 7cm × 1cm.

Calculate the areas:

A₁ = 15 · 2 = 30 cm²

A₂ = 7 · 1 = 7 cm²

The area of the figure:

A = A₁ + A₂ → A = 30 cm² + 7 cm² = 37 cm²

5 0
3 years ago
Help please! I'll give a brainliest for the best and the correct answer loves!
Fofino [41]
15x10=150
Subtract 5x5=25 small square cut out
150 -25= 125 sq ft
D
3 0
3 years ago
How many solutions does the following equation have ? -3x+9-2x=-12-5x?
Maurinko [17]

Answer:

0.....................

5 0
3 years ago
Which of the following functions is graphed below?
yanalaym [24]

Answer:

c) l x - 5 l - 4

Step-by-step explanation:

when you're graphing functions whatever is inside the paranthesis, square root or absolute value determines whether you go left or right, if its a negative you go to the right, if its positive you go to the left. So the opposite of what you would expect it to go

in this instance its - 5, so you go 5 units to the right

and the number outside determines if you go up or down, in this question its - 4 so you go down 4 units

7 0
2 years ago
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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