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kondor19780726 [428]
3 years ago
10

Buffalo Bill currently weighs 202 lb. He wants to weigh 180 lbs for his reunion which is 35 days from today. How many pounds per

week must he lose?
Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

He must lose 4.4 pounds per week.

Step-by-step explanation:

Buffalo Bill currently weighs 202 lb. He wants to weigh 180 lbs for his reunion.

This means that he needs to lose 202 - 180 = 22 lb.

35 days from today.

Each week has 7 days. So this is 35/7 = 5 weeks from now.

How many pounds per week must he lose?

22 pounds in 5 weeks, that is 22/5 = 4.4 pounds per week.

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Rewrite the expression  6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$

The ratio of \frac{q}{p}  = - 34

How to solve such questions?

Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.

Completing the square is a method that is used for converting a quadratic expression of the form ax^{2} + bx + c to the vertex form

a(x - h)^{2} + k. The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: a(x + m)^{2} + n, such that the left side is a perfect square trinomial

$6j^2 - 4j +12$

=  $6(j^2 - \frac{2}{3} j )+12$

= $6(j^2 - \frac{2}{3} j  +  \frac{1}{9}  )+\frac{102}{9}                   (Completing Square method)

=6( j- \frac{1}{3} )^{2}  +  \frac{34}{3}

On comparing with the given equation we get

p = - \frac{1}{3}     and q = \frac{34}{3}

∴ \frac{q}{p} = \frac{\frac{34}{3} }{\frac{-1}{3} }

= - 34

Learn more about completing the square method here :

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