Answer:
Rounding to the nearest minute, it would take 95 minutes, or 1 hour and 35 minutes.
Step-by-step explanation:
Let's convert each time to minutes:
3.2 hours = 192 minutes
80 minutes = 80 minutes
2 hr 20 min = 140 minutes
Next, let's find the least common multiple:
LCM(192, 80, 140) = 6720
So let's say the volume of the tank is 6720 units. The speed of each pump is therefore:
Pump 1 = 6720 units / 192 minutes = 35 units/minute
Pump 2 = 6720 units / 80 minutes = 84 units/minute
Pump 3 = -6720 units / 140 minutes = -48 units/minute
Their combined speed is:
35 + 84 − 48 = 71 units/minute
So the time to fill the tank is:
6720 units / (71 units/minute) = 94.65 minutes
Rounding to the nearest minute, it would take 95 minutes, or 1 hour and 35 minutes.
Answer: The lamppost is 7 feet 2 inches
Step-by-step explanation: If Ann measured her own height and her shadow, then what she used is a ratio between both measurements. If she can measure the shadow of the lamppost, then she can use the same ratio of her height and it’s shadow to derive the correct measurement of the lamppost.
If Ann’s height was measured as 5 feet 3 inches, and her shadow was 8 feet 9 inches, the ratio between them can be expressed as 3:5.
Reduce both dimensions to the same unit, that is, inches. (Remember 12 inches = 1 foot)
Ratio = 63/105
Reduce to the least fraction
Ratio = 3/5
If the height of the lamppost is H, then
H/144 = 3/5
H = (144 x3)/5
H = 86.4
Therefore the lamppost is approximately 86 inches, that is 7 feet and 2 inches tall.
Answer:
36
Step-by-step explanation:
Rewrite this as
(2)(3)(√3)(√12), or
6 * √36, or
6 * 6 = 36
Your answer is x=1.243927
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
