What are 2 fractions equivalent to 1/12

A fish tank is filled with water.The tank holds 150 gallons.Each cubic foot of water contains about 7.5 gallons.The rank is 5 fe

san4es73 [151]

Answer:

Width = $1\frac{1}{3}$ ft

Step-by-step explanation:

The tank holds 150 gallons of water.

7.5 gallons holds 1 ft³ of water.

So 150 gallons will hold;

$\frac{150}{7.5}$ × 1 ft³ = 20 ft³

The volume of the tank = Length(l) × Width(w) × Height(h) = 20 ft³

i.e 5 ft × w × 3 ft = 20 ft³

15w ft² = 20 ft³

w = $\frac{20 ft^3}{15 ft^2}$ = $1\frac{1}{3}$ ft

6 0

4 years ago

the angel of elevation from where casey is standing to the top of an 84ft tall lighthouse is 58 degrees how far is casey standin

In-s [12.5K]

Answer: 52.489…

Step-by-step explanation:

Angle of elevation is 58 degrees, and the opposite value is 84 feet, so you’re lookin g for adjacent. That means you’ll use tangent to solve this equation:

Tan(58)=84/x

5 0

4 years ago

Read 2 more answers

Your bag of rice says to mix 1 cup of rice with 2 cups of water. dela requ prov a. What is the ratio of rice to water? refer to

EastWind [94]

Answer:

(a) 1:2

(b) 6 cups

(c) $\dfrac{2}{3}$

Step-by-step explanation:

(a) Given,

amount of rice mixture contains= 1 cup

amount of water mixture contains= 2 cups

$\textrm{So, the ratio of rice to water}\ =\ \dfrac{\textrm{amount of rice in mixturte}}{\textrm{amount of water in mixture}}$

$=\ \dfrac{1}{2}$

So, the ratio of rice to water is 1:2.

(b) Amount of rice in mixture = 3 cups

$\textrm{So, the ratio of rice to water}\ =\ \dfrac{\textrm{amount of rice in mixturte}}{\textrm{amount of water in mixture}}$

$=>\ \dfrac{1}{2}\ =\ \dfrac{3}{\textrm{amount of water in mixture}}$

=> amount of water in mixture = 3 x 2

= 6 cups

(c) $\textrm{amount of rice in mixture}\ =\dfrac{1}{3}$

$\textrm{So, the ratio of rice to water}\ =\ \dfrac{\textrm{amount of rice in mixturte}}{\textrm{amount of water in mixture}}$

$=>\ \dfrac{1}{2}\ =\ \dfrac{\dfrac{1}{3}}{\textrm{amount of water in mixture}}$

$=>\textrm{amount of water in mixture}\ =\ \dfrac{2}{3}$

So, the amount of water in the mixture will be $\dfrac{2}{3}$ cup.

7 0

3 years ago

The ratio of boys to girls in a school is 5:4. if there are 180 students, how many girls are there?

vladimir2022 [97]

Salutations!

The ratio of boys to girls in a school is 5:4. if there are 180 students, how many girls are there?

Let the number of girls and boys be 'x'.

 $5x + 4x = 180$

Add 5 and 4

 $9x = 180$

 $x = 20$

Now, multiply the ratios by 20.

Boys = 20 × 5 = 100

Girls = 20 × 4 = 80.

There were 80 girls.

Hope I helped (:

Have a great day!

4 0

4 years ago

Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f

almond37 [142]

Answer:

The probability is 0.001812

Step-by-step explanation:

Let's call: F the event in which a user is fraudulent, L the event in which a user is legitimate and A the event in which the user calls from two or more metropolitan areas.

So, the probability that the user is fraudulent given that the user call from two or more metropolitan areas is calculated as:

P(F/A) = P(F∩A)/P(A)

Where P(A) = P(F∩A) + P(L∩A)

So, P(F∩A) is the probability that the user is fraudulent and the user calls from two or more metropolitan areas. it is calculated as:

P(F∩A) = 0.0121% * 30% = 0.00363%

Because 0.0121% is the proportion of fraudulent users and 30% is the percentage of the fraudulent users that call from two or more metropolitan areas in a single day.

At the same way, P(L∩A) is the probability that a user is legitimate and the users calls from two or more metropolitan areas. It is calculated as:

P(L∩A) = (100%-0.0121%) * 2% = 1.999758%

Because (100%-0.0121%) is the proportion of legitimate users and 2% is the percentage of the legitimate users that call from two or more metropolitan areas in a single day.

Then, P(A) is calculated as:

P(A) = 0.00363% + 1.999758%

P(A) = 2.003388%

Finally, If the same user originates calls from two or more metropolitan areas in a single day, the probability that the user is fraudulent, P(F/A), is equal to:

P(F/A) = 0.00363 / 2.003388

P(F/A) = 0.001812

5 0

3 years ago