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ser-zykov [4K]
3 years ago
6

The (blank) of a conditional switches the hypothesis and conclusion

Mathematics
1 answer:
Elanso [62]3 years ago
4 0
The converse of a conditional statement switches the hypothesis and conclusion.
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If x+1/x=7,find x^2+1/x^2​
trapecia [35]

Answer:

x²+1/x² = 51

Explanation:

Given x - 1/x = 7 ---(1)

We know the algebraic identity:

a²+b²-2ab = (a-b)²

Or

a²+b² = (a-b)²+2ab

Now,

x²+1/x²

= (x-1/x)²+2*x*(1/x)

= (x-1/x)²+2

:7²+2 [ from (1)] =

= 49+2

= 51

Therefore,

x²+1/x² = 51

3 0
2 years ago
Please help with this problem how to solve from percent to fraction?
Nana76 [90]
First, divide the percent by 100. Then if the percent is not a whole number, then multiply the top and bottom by 10 for every number after the decimal point. :)
8 0
2 years ago
Read 2 more answers
Solve the following equation and show all the steps to solving.
Bumek [7]
\bf \cfrac{x}{x-2}+\cfrac{x-1}{x+1}=-1\impliedby LCD\to (x-2)(x+1)\\\\
-------------------------------\\\\
\cfrac{x(x+1)+(x-1)(x-2)}{(x-2)(x+1)}=-1
\\\\\\
x^2+x+x^2-3x+2=-1(x-2)(x+1)
\\\\\\
2x^2-2x+2=-1(x^2-x-2)\implies 2x^2-2x+2=-x^2+x+2
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3x^2-3x=0\implies 3x(x-1)=0\implies 
\begin{cases}
3x=0\implies &x=0\\
x-1=0\implies &x=1
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8 0
2 years ago
2³+2²+2÷2²+2+1=2 prove that this relation is true for any natural numbers
UkoKoshka [18]

So, this question is basically asking us "If we had an x instead of a 2, would this be true?" We can try and see what we get:

\frac{x^3+x^2+x}{x^2+x+1}=x

So, if we want to show this we have to change the numerator or denominator in such a way that we can cancel some common factors. Notice that x^3+x^2+x=x(x^2+x+1)

If we replace the factored numerator with the original one, we get:

\frac{x(x^2+x+1)}{x^2+x+1}=x \implies \\ x=x

Since we have an equality, this relation is proved.

3 0
3 years ago
My number has more tens blocks than ones blocks. My number name starts with fifty.
ozzi
Couldn't it be 54, 53 52, or 51
5 0
2 years ago
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