Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer:
No solution
Step-by-step explanation:
-3x + 3y = 4
-x + y = 3
<u>Solve the equation for x:</u>
<u>Move the variable to the right side and change its sign</u>
-x + y = 3
-x = 3 - y
<u>Change the signs on both sides of the equation</u>
-x = 3 - y
x = -3 + y
<u>Substitute the given value of x into the equation -3x + 3y = 4</u>
-3x + 3y = 4
x = -3 + y
-3(-3+y)+3y=4
<u>Solve the equation for y</u>
-3(-3+y)+3y=4
y = 0
There is no solution for y.
And since there's no solution for y, the system has no solution.
Answer:
I think C 45 blocks are the right answer.
If y=mx+b,
You can't differentiate a constant, so dy/dx=m.
Answer:
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length= 42, width=12, depth=8</h2>
Step-by-step explenation:
